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hv
             photonics

Article
Gyrotropic Crystals as a Basis for Creation of Helical
Polychromatic Singular Beams
Yuriy Egorov *           and Alexander Rubass


                                         Physics and Technology Institute, V.I. Vernadsky Crimean Federal University, Vernadsky Prospect 4,
                                         295007 Simferopol, Russia; alex.rubass@gmail.com
                                         * Correspondence: yuriyegorov@cfuv.ru

                                         Abstract: In this work, studies are carried out in the field of optical singular beams that have passed
                                         through gyrotropic crystals. We have experimentally shown that singular beams with a helical
                                         intensity distribution are formed when passing through a system of two gyrotropic crystals with
                                         opposite values of the gyration coefficient. It is shown that the system is capable of generating optical
                                         vortices with a double topological charge in one of the components of circular polarization when
                                         light propagates through two gyrotropic crystals.

                                         Keywords: polychromatic singular beams; gyrotropic crystals; topological charge




                                         1. Introduction
                                               In modern singular optics, special attention is paid to beams carrying the so-called
                                         optical vortices and those carrying a topological charge [1]. In the mid-1990s, such beams
                                         in free space were obtained experimentally [2,3]. It was then that an intensive experimental
                                         study of singular beams began. Around the same time, it was discovered that rays with
                                         optical vortices carry angular momentum [4,5]. Particular interest in beams containing
                                         optical vortices has increased significantly due to the fact that such beams can be used to
                                         create optical tweezers and similar objects.
                                               However, the creation of single optical vortices carried by paraxial beams of the
                                         Laguerre–Gauss and Bessel–Gauss types faces serious technical difficulties. The point is
                                         that the traditional method of obtaining optical vortices is based on light diffraction either
Citation: Egorov, Y.; Rubass, A.
                                         on computer-synthesized holograms [2,3] or on spiral phase plates [6,7]. These methods are
Gyrotropic Crystals as a Basis for
                                         based on strict observance of the diffraction conditions near the phase singularity and are
Creation of Helical Polychromatic
                                         critical to the wavelength. In this case, special mention should be made of optical beams
Singular Beams. Photonics 2023, 10,
1044. https://doi.org/10.3390/
                                         that have the property of Fourier invariance [8,9]. However, in [10–12], it was possible
photonics10091044
                                         to avoid such stringent requirements for the formation of an optical vortex due to the
                                         processes of light propagation in a uniaxial anisotropic medium. It has been shown that
Received: 14 August 2023                 a circularly polarized beam propagating along the optical axis of an anisotropic medium
Revised: 6 September 2023
                                         is capable of forming optical vortices on the axis with the same localization, regardless of
Accepted: 12 September 2023
                                         the wavelength.
Published: 14 September 2023
                                               Traditional concepts of a linearly polarized paraxial beam passing along the optical
                                         axis of a uniaxial crystal suggest that at the exit from the crystal after passing through the
                                         polarizer, the beam forms an intensity distribution in the form of a Maltese cross [13]. This
Copyright: © 2023 by the authors.
                                         pattern is a distinctive feature of a uniaxial crystal.
Licensee MDPI, Basel, Switzerland.             From the point of view of polarization features, the conoscopic pattern arises as a result
This article is an open access article   of the superposition of two circularly polarized beams carrying vortices with a double
distributed under the terms and          topological charge of the opposite sign. In fact, this picture is a field with perpendicular
conditions of the Creative Commons       edge dislocations.
Attribution (CC BY) license (https://          When the beam is tilted relative to the optical axis or when external perturbations are
creativecommons.org/licenses/by/         introduced, the double vortices leave the beam, and the structure of edge dislocations un-
4.0/).                                   dergoes structural transformations. The bulk of theoretical and experimental studies [14,15]



Photonics 2023, 10, 1044. https://doi.org/10.3390/photonics10091044                                       https://www.mdpi.com/journal/photonics

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Photonics 2023, 10, 1044                                                                                                         2 of 15




                           mainly concerns the study of the structure of conoscopic patterns arising in axial beams.
                           Conoscopic carines are interference patterns in a converging polarized beam obtained in
                           crossed polarizers, between which the anisotropic medium under study is located. The
                           conoscopic pattern corresponding to the circular state of polarization on the input face of
                           an anisotropic crystal is localized in the focal plane of the objective. However, it also has
                           the shape of concentric rings, and near the beam axis there are four topological dipoles
                           separated by bright stripes. Any disturbance of the axial extension is considered to be a per-
                           turbation of the conoscopic pattern. However, this process hides various transformations
                           of polarization features caused by weak perturbations.
                                 It should be noted that the studies [16–18] are devoted to the study of the structure
                           of polarization features in low-order Laguerre–Gauss beams that arise after excitation of
                           the crystal by linearly polarized light. The authors of these papers focused on linearly
                           polarized beams. Their model is based on two linearly polarized beams carrying optical
                           vortices (ordinary and extraordinary) propagating at slightly different angles.
                                 As is known, uniaxial and biaxial crystals serve as basic elements for the generation
                           of optical vortices embedded in various types of singular beams [19]. The most amazing
                           feature of the crystal is the ability to create stable polychromatic vortices with high energy
                           efficiency. In contrast to the method of computer holograms [20–22], the crystal forms a
                           white vortex beam without any additional devices [23].
                                 The purpose of this article is to consider another method that allows one to gen-
                           erate singular beams carrying screw edge dislocations and optical vortices using two
                           gyroanisotropic crystals. Before considering the method of generating singular beams
                           carrying optical vortices using two gyroanisotropic crystals, it is necessary to evaluate the
                           influence of a gyrotropic crystal on the wave front.

                           2. Gyroanisotropic Crystals
                                First, it should be noted that a gyrotropic crystal is a space that does not only have
                           linear birefringence (that is, space is able to transform circularly polarized light into linearly
                           polarized, and vice versa), but also circular birefringence (that is, space is able to rotate
                           linear polarization). Even in simple cases, electrical vector D and magnetic vector H are
                           expressed in a complex way:

                                                           D = ε̂E + g rotE,      B = H + g0 rotH .                                 (1)

                                To estimate the effect of a gyrotropic crystal on a singular beam, we chose the Jones
                           matrix method, which we have already used for anisotropic crystals in [19]. Consider the
                           propagation of a beam through an element of a gyrotropic crystal along its optical axis. The
                           optical axis coincides with the z axis. The input face of the crystal is located on the plane
                           z = 0. A linearly polarized Gaussian beam is incident normally on the input face of the
                           crystal. As was shown in [19], a Gaussian beam can be represented as a set of rectilinear
                           rays distributed in space along a hyperboloid of revolution. Figure 1 shows one of these
                           beams directed at the crystal at an angle δ to its optical axis. The birefringence axes are in
                           the same plane as the optical axes and form an angle φ with the y-axis.
                                The beam passes through the element dz of the crystal. The beam polarization trans-
                           formation Ein can be written in matrix form:

                                                                          Eout = ĝEin                                              (2)

                           where
                                          ?                                                           ??       γ         γ   ?
                                                   δ
                                              cos 2N           δ
                                                      + i sin 2N cos 2φ               δ
                                                                               i sin 2N sin 2φ             cos N   − sin N
                                   ĝ =                                                                        γ        γ           (3)
                                                          δ
                                                   i sin 2N sin 2φ        cos 2N − i sin 2N
                                                                               δ          δ
                                                                                             cos 2φ        sin N    cos N
                                                                                                            2
                           and where N is the number of layers in a crystal, δ = k∆n L √ 2r                     is the phase differ-
                                                                                                       r + d2
                           ence between the ordinary E(o) and extraordinary E(e) components of the beam that has

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                                      passed
                      Photonics 2023, 10, x FOR through a crystal of length d, ∆n L = n
                                                PEER REVIEW
                                                                                                   e − no is linear birefringence, no and ne

                                     are values√for the ordinary and extraordinary refractive indices, k is the wave number,
                                     γ = k∆nC r2 + d2 is the full rotation (gyration) of the electric vector, and ∆nC is the value
                                     for circular birefringence.




                                     Figure 1. Scheme of  beam1.propagation
                                                        Figure              through
                                                                 Scheme of beam     a gyrotropic
                                                                                 propagation     uniaxial
                                                                                             through      crystal; longitudinal
                                                                                                      a gyrotropic              (a) A‘B‘
                                                                                                                     uniaxial crystal; longitudina
                                     and transverse (b) AB.
                                                        and transverse (b) AB.

                                    As the thickness The  of the
                                                              beamcrystal
                                                                        passeselement
                                                                                  through   tends
                                                                                                the to  zero, d
                                                                                                    element      ∆zz of→the0 , and    at N
                                                                                                                                 crystal. The→beam∞ , wepolarizatio
                                have:             ?formation        in
                                                                  E      can  be   written     in
                                                                                               ?  matrix
                                                                                                  ?         form:
                                                                                                             γ  ?
                                                          δ
                                                   1 + i 2N  cos 2φ            δ
                                                                            i 2N   sin 2φ           1 −N
                                           ĝ ≈                                                     γ                = 1̂ + ∆ˆ N + γ̂ N ,             (4)
                                                        δ
                                                     i 2N sin 2φ          1 − i 2Nδ
                                                                                      cos 2φ        N      1 out
                                                                   ?                            ?             E = gˆ?E      in
                                                                                                                                     ?
                                                      ˆN = i           cos 2φ       sin   2φ                               0 −1
                                where matrices are ∆            δ
                                                               2N sin 2φ − cos 2φ                 and     γ̂ N  =     γ
                                                                                                                      N                 .
                                                   where                                                                   1       0
                                    For the total length of the crystal, we have:
                                                                             δ              δ                              δ ? ?                   γ          γ
                                                                                                 cos 2 φ d ?∆                        2 φ.
                                                                                                    ?Z
                 Ĝ = lim N →∞ ∏ 1 + ∆ˆ N + γ̂ N ≈ lim N →∞ ∏ exp      cos∆ˆ N ++ γ̂i sin? = exp             ˆ     i)sin        sin            cos (5) − sin
                                                ?
                                                                            2N         N 2N                     ( z   +  γ̂
                                                                                                                          2N( z ) dz                  N         N
                                                               gˆN=                                    0                                     
                                                                                     δ                            δ               δ                γ         γ
                                                                             i sin        sin 2 φ          cos         − i sin       cos 2 φ   sin       cos
                                Define the form Ĝ                                  2N                           2N              2N                N         N
                                                                                                    N                            N
                                             Ĝ = lim N →∞ ∏ exp ∆     ˆ N + γ̂ N = lim exp ∑ (∆        ˆ N + γ̂ N ) = lim exp ∑ µ N r 2
                                                                                  ?
                                                                                                                                            (6)
                                                        and where N is the number of layers in a crystal, δ = k Δ nL                         is the pha
                                                              N                                     1                            1
                                                                                                                                     r +d
                                                                                                                                      2   2


                                                                                            E(2φ
                                                                                              o)
                                                                                                                          E( ) components of the beam
                                                                                                                            e
                                                                                                                            !
                                                        ence between the ordinary   iδN
                                                                                        cos        and extraordinary
                                                                                                       −  γN
                                                                                                              +  iδN
                                                                                                                     sin 2φ
                                                         N = ∆N
                                                               ˆ   + γ̂ N =a crystal2N                     N     2N                         (7) no and
                                                       µpassed   through        γN      iδNlength d, Δn =
                                                                                       of                      ne − no is linear birefringence,
                                                                                                             iδN
                                                                                 N + 2N sin 2φ             −
                                                                                                           L
                                                                                                             2N cos 2φ
                                                        values for the ordinary and extraordinary refractive indices, k is the wave
                                     Rewrite Ĝ in the form:
                                                        γ = k ΔnC r 2 + d 2 is the fullc rotation
                                                                                                −s (gyration) of the electric vector, and ΔnC is t
                                                                                       ?            ?
                                                                                Ĝ =                                                        (8)
                                                        for circular birefringence. s∗ c∗
                                                N             As theNthickness
                                                                       ?           of the crystal
                                                                                              ?       element tends to zero, Δz → 0 , and at N →
                                     where c = ∑ i 2N
                                                    δN
                                                        cos 2φ, s = ∑ γNN − iδ
                                                        have:                     N
                                                                                 2N   sin 2φ    , and * signifies complex conjugation.
                                                   1                     1
                                           Refine the matrix Ĝ. The matrix Ĝ has its own values:
                                                                                    δ                  δ                   γ 
                                                                         ? 1+ i             2φ
                                                                                         cos ?       i      sin 2 φ   1 − 
                                                                           λ  −
                                                                        gˆ ≈  ∗ c  2 N  s             2 N                 N   = 1ˆ + Δˆ (9)
                                                                                                                                              + γˆN ,
                                                                                                = 0,
                                                                            − s δ λ − c∗                 δ             γ     
                                                                                                                                            N

                                                                              i       sin 2 φ      1− i      cos 2 φ      1 
                                                                              2 Ns                      2N            N      
                                                                                ∗                  2
                                                                          c+c            (c + c∗ )       2.
                                                                    λ=             ± δ  cos 2 φ − ssin      2φ               γ  0 −(10)1
                                                       where matrices are 2Δˆ N = i          2                    and γˆN =               .
                                                                                       2 N  sin 2 φ − cos 2 φ                N1 0 
                                                            For the total length of the crystal, we have:


                                                                                    (              )                     (          )        (
                                                                  Gˆ = lim N →∞ ∏ 1 + Δˆ N + γˆN ≈ lim N →∞ ∏ exp Δˆ N + γˆN = exp   Δˆ ( z ) + γˆ ( z ) 
                                                                                                                 N
                                                                                                                                    d

                                                                                                                                                 0

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Photonics 2023, 10, 1044                                                                                                                          4 of 15




                           Write the equation for eigenvectors:

                                                                  (c − λ)h1 − sh2 = 0,                                                             (11)

                           where h1 and h2 are the eigenvectors of the matrix Ĝ. Then,
                                                                                                        q                         !
                                                                  1                      c−c∗               ( c + c ∗ )2
                                                   h1 = q                                 2 +                    2       − s2           ,          (12)
                                                            ( c + c ∗ )2                                    s
                                                                 2       − s2
                                                                                                        q                         !
                                                                  1                      c∗ −c              ( c + c ∗ )2
                                                   h2 = q                                  2 −                   2       − s2           .          (13)
                                                            ( c + c ∗ )2                                    s
                                                                 2       − s2
                           Compose from h1 and h2 the matrix H, the columns of which are the vectors h1 and h2 :
                                                                               r                                    r                       
                                                                  c−c∗ +            ( c + c ∗ )2          c∗ −c −        ( c + c ∗ )2
                                                                    2                    2       − s2       2                 2       − s2
                                                    ? ?               r                                        r                            
                                                     h1                    ( c + c ∗ )2                            ( c + c ∗ )2
                                                                                                                                             
                                              H=        =                       2       − s2                            2       + s2        .    (14)
                                                     h2  
                                                                                   s                                       s
                                                                                                                                             
                                                                                                                                             
                                                                       r                                        r
                                                                            ( c + c ∗ )2                            ( c + c ∗ )2
                                                                                 2       − s2                            2       + s2


                           Matrix H −1 , the inverse of matrix H, has the form:
                                                                                                         r                       
                                                                                                c−c∗ +        ( c + c ∗ )2
                                                                                                  2                2       − s2
                                                        r                  s                       r                      
                                                         ( c + c ∗ )2 2                                ( c + c ∗ )2
                                                                                                                           
                                                     −1        2      −s                                             − s2
                                                                                                         r2
                                                                                                                          
                                                    H =                                                             2
                                                                                                                           .                      (15)
                                                                                               c∗ −c −            ∗
                                                                                                              (c+c )
                                                                                                                           
                                                                                                                        2
                                                                                                                       −s 
                                                        r s                                      2              2         
                                                                                                    r
                                                                      ( c + c ∗ )2                      ( c + c ∗ )2
                                                                           2       + s2                      2       + s2

                           Further:
                                                                 N
                                                         G = exp ∑ µ N = H exp ∆
                                                                               ˆ N H −1 .
                                                                                  ?
                                                                                                                                                   (16)
                                                                        1

                           Using the matrix eigenvalue equation:

                                                                    ˆ N σi = (exp ηi )σi .
                                                                exp ∆
                                                                       ?
                                                                                                                                                   (17)

                           where σi and ηi are the eigenvectors and eigenvalues of the matrix ∆     ˆ N.
                               Rewrite the matrix Ĝ in the form:
                                                                                                         
                                                                                 γ+i 2δ sin 2φ
                                                 cos Λ + i 2 Λ sin Λ cos 2φ
                                                             δ
                                                                                       Λ       sin Λ
                                         Ĝ =       −γ+i 2δ sin 2φ
                                                                                                          .                                       (18)
                                                         Λ          sin Λ   cos Λ −    i  δ
                                                                                         2Λ  sin Λ cos 2φ

                           where Λ2 = (δ/2)2 + γ2 . Expression (18) is called the generalized Jones matrix.

                           3. Transformation TE and TM Modes in a Gyrotropic Crystal
                                The above Matrix (18) describes the transformation of the polarization state of a beam
                           propagating in a gyrotropic crystal. A linearly polarized Gaussian beam passing through a
                           crystal undergoes structural changes. One example of such a change is shown in Figure 2.

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Photonics 2023, 10,
                10, x1044
                      FOR PEER REVIEW                                                                                                  6 of5 18
                                                                                                                                             of 15




                                  Figure2.2.Field
                                 Figure             structureofofa alinearly
                                             Fieldstructure            linearlypolarized
                                                                                polarized Gaussian
                                                                                         Gaussian    beam
                                                                                                  beam   (a)(a) after
                                                                                                             after    passing
                                                                                                                   passing    through
                                                                                                                           through    a gyrotropic
                                                                                                                                   a gyrotropic
                                                ∆n         ·    −-33, ∆n = 3 · 10−5 ,-d5 = 1 cm; (b) long-range order of the field ∆n = 2 · 10−3 ,
                                 crystal with D
                                  crystal with      L nL = 2 ⋅ 10
                                                       = 2   10        , CD nC = 3 ⋅10 , d = 1cm ; (b) long-range order of Lthe field
                                  ∆nnC =       -3−5 , d = 1 cm. -5
                                            · 10
                                       =23⋅ 10
                                 D      L        , D n = 3 ⋅ 10 , d = 1cm .
                                                         C


                                       At the same time, it is interesting to consider the transformation of the beam mode
                                       At the same time, it is interesting to consider the transformation of the beam mode
                                  fields depending on their own polarization, which they had in a simple anisotropic crystal.
                                 fields depending on their own polarization, which they had in a simple anisotropic crystal.
                                  As is known [16,17], such beams are TE and TM modes [24] with the following polariza-
                                 As is known [16,17], such beams are TE and TM modes [24] with the following polariza-
                                  tion state:
                                 tion state:                                   ?
                                                                                  sin φ
                                                                                          ?
                                                                      | TEi =               G                             (19)
                                                                                 − cos φ 01
                                                                                sin φ ? 
                                                                          TE = ?         G01                         (19)
                                                                       | TMi =  −cos
                                                                                   cos φ
                                                                                       φ  G01 ,                          (20)
                                                                                   sin φ
                                    where Gm=0, l =1 is the complex amplitude of the paraxial beam with indices m = 0, l = 1.
                                         The results of the action of the Matrix   cos φ on the fields TE and TM are shown in
                                                                                     (18)
                                                                           TM =          G ,                                 (20)
                                    Figure 3. The straight lines of the TE and TM sin
 Photonics 2023, 10, x FOR PEER REVIEW                                                  φ  01that can be observed on the7input
                                                                                     modes                                 of 18 face
                                    of a gyrotropic crystal become twisted in a spiral, and with the opposite twist, as the beam
                                    where G along
                                    propagates         thecomplex
                                                   is the
                                            m= 0, l =1
                                                           crystal. amplitude of the paraxial beam with indices m = 0 , l = 1 .
                                       The results of the action of the Matrix (18) on the fields TE and TM are shown in
                                 Figure 3. The straight lines of the TE and TM modes that can be observed on the input face
                                 of a gyrotropic crystal become twisted in a spiral, and with the opposite twist, as the beam
                                 propagates along the crystal.




                                                                                                                                            −3
                                 Figure3.3.Transformation
                                 Figure     TransformationTETE(a)(a) and
                                                                   and TMTM
                                                                          (b)(b)
                                                                              of of mode
                                                                                 mode       in aingyrotropic
                                                                                         beams
                                                                                      beams        a gyrotropic  crystal:
                                                                                                             crystal: D nL∆n     10-23 ·, 10 ,
                                                                                                                           = L2 ⋅=
                                 ∆nnC =    · 10
                                      =33⋅10    − 5
                                 D      C
                                             -5
                                                , d, d== 1 cm.
                                                       1cm  .

                                      The longer the crystal, the more the direction of the major semiaxis of the polarization
                                 vector twists. Moreover, the linear polarization becomes elliptical. Thus, the TE and TM
                                 modes are not eigenmodes of a gyrotropic crystal. To determine the intrinsic polarization

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                                The longer the crystal, the more the direction of the major semiaxis of the polarization
                           vector twists. Moreover, the linear polarization becomes elliptical. Thus, the TE and TM
                           modes are not eigenmodes of a gyrotropic crystal. To determine the intrinsic polarization
                           of the beam, consider the characteristic equation:

                                                                                  −γ+i 2δ sin 2φ
                                         cos Λ + i 2δΛ sin Λ cos 2φ − η                Λ         sin Λ
                                                γ+i 2δ sin 2φ
                                                                                                            = 0.       (21)
                                                      Λ       sin Λ         cos Λ − i 2Λ sin Λ cos 2φ − η
                                                                                       δ


                           It follows that the eigenvalues are:

                                                                      η = exp(±i Λ).                                   (22)

                           Therefore, the eigenvectors of Matrix (18) have the form:
                                                             γ !
                                                                                       ?                 ?!
                                               δ
                                              2 Λ sin 2φ + i Λ ?                     −               −
                                           1                                       1      δ
                                                                                         2Λ   cos 2φ   1
                                        +
                                       m =    ?                  ,            m− =                          ,          (23)
                                           N − 2δΛ cos 2φ − 1                      N    δ
                                                                                            sin 2φ − i γ
                                                                                            2Λ              Λ
                                       q
                           where N = 2 − Λδ cos 2φ.
                                The field structure of eigenmodes is a system of ellipses. Each of these ellipses has
                           its own ellipticity Q and azimuth angle φ. Write the Stokes parameters S j ( j = 0, 1, 2, 3)
                           using Expression (23). We receive:

                                                           S0 = N 2          ?            ?
                                                           S1 = − 2Λ
                                                                   δ
                                                                     cos 2φ 2 − Λδ cos 2φ
                                                                          ?             ?                              (24)
                                                                 δ
                                                           S2 = 2Λ sin 2φ 2 − Λδ cos 2φ
                                                                     ?              ?
                                                                   γ
                                                           S3 = − 2Λ   2 − Λδ cos 2φ .

                           Therefore, the azimuth angle of the major axis of the ellipse is:

                                                                  tan 2ψ = SS2 = tan 2φ
                                                                             1                                         (25)
                                                                  or ψ = φ.

                           The angle of ellipticity χ can be written as:

                                                                       sin 2χ = S3 .                                   (26)

                           This is in connection with:
                                                                            S3  γ
                                                                       q=      = .                                     (27)
                                                                            S0  Λ
                           Define the ellipticity of the beam:

                                                                 b               q
                                                           Q=      = tan χ =    p       .                              (28)
                                                                 a           1 − 1 − q2

                           Given the very weak gyration of the crystal (which is the case for real crystals δ >> γ)
                           away from the axes, the ellipticity will be represented as:

                                                                           γ       δ
                                                                  Q=            ≈    .                                 (29)
                                                                        Λ − δ/2   2γ

                                Beam eigenmodes in a simple gyrotropic crystal have a nonuniform distribution of
                           polarization over the beam cross section. Their polarization components do not have phase
                           singularities (except for the axial case). On the axes, the eigenfields are circularly polarized,
                           as shown in Figure 4.

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 Photonics 2023, 10, 1044                                                                                                                     7 of 15




                                  Figure 4. Self-polarized beams m+ (a) and m− (b).
                                 Figure 4. Self-polarized beams m + (a) and m − (b).
                                        As we move away from the center (see Figure 4a,b), the ellipticity of the polarization
                                  stateAs  we moveuntil
                                        decreases      away thefrom
                                                                 lightthe center (see
                                                                       eventually         Figure linearly
                                                                                     becomes      4a,b), the  ellipticity of the polarization
                                                                                                            polarized.
                                 state decreases until the light eventually becomes linearly polarized.
                                  4. Propagation of a Beam through Two Gyroanisotropic Crystals
                                 4. Propagation
                                        Consider of theapropagation
                                                          Beam through    of aTwo
                                                                                beamGyroanisotropic        Crystals crystals with different
                                                                                        through two gyrotropic
                                  values   of circular
                                       Consider    the birefringence
                                                        propagation of   ∆naCbeam
                                                                               . The rest   of thetwo
                                                                                      through       crystal  parameters
                                                                                                         gyrotropic        remain
                                                                                                                     crystals  withthe    same.
                                                                                                                                     different
                                 valuesFor
                                         of this       it is necessary toΔmultiply
                                                 case, birefringence
                                             circular                                 two of
                                                                           nC . The rest    matrices   [3] with
                                                                                               the crystal      the difference
                                                                                                             parameters         γ1 =
                                                                                                                           remain   the−same.
                                                                                                                                          γ2 = γ.
                                  After applying linear algebra, we have
                                       For this case, it is necessary to multiply two matrices [3] with the difference
                                 γ 1 = −γ 2 = γ . After applying linear algebra,     ? we have ?
                                                                                          C11 C12
                                                                            D Ĝ =           ∗     ∗ ,                                       (30)
                                                                                        −C12     C11
                                                                                         C      C12 
                                                                                 DGˆ =  11∗
                                                                                                 ?∗ 
                                                                                                       ,                                    (30)
                                                  2
                                                          ?
                                                              2     2
                                                                        ? sin2 Λ          −
                                                                                        δ 12 C11 
                                                                                           C                         γ                ?
                                      C11 = cos Λ + γ − δ /4                       +  i    sin Λ   cos   Λ cos 2φ −     sin Λ  sin 2φ   ,    (31)
                                                                            Λ2          Λ                            Λ

                                                                                 sin 2 Λ δ          γ in Λ cos 2φγ .                 
                                                            + ( γ=2 i− δ 2sin
                                                                           / 4 )Λ cos
                                                                       δ          ?                                    ?
                                              C11 = cos 2 ΛC12                          Λ
                                                                                        + i
                                                                                          sin sin
                                                                                              2φ  Λ
                                                                                                  + Λcos Λ cos 2 φ −    sin Λ sin 2φ  ,       (32)
                                                                                                                                               (31)
                                                                      Λ            Λ2       Λ                         Λ              
                                        The eigenvalues η of Matrix (6) have the form
                                                                                                          r
                                                                                  ? sin2 Λ
                                                                     2 δ 2                      δ γ                       2
                                                                                                                     γ
                                                                 ?
                                                        2
                                               η = cos Λ +C12γ= −       i δsin                         Λ Λcos
                                                                                            ± i2φ +sin sin
                                                                              /4Λ  cos2Λ sin                cos2 2Λ
                                                                                                                   φ +. 2 sin2 Λ.              (33)
                                                                                                                                               (32)
                                                                         Λ           Λ         Λ Λ                   Λ
                                       Thus, the eigenvectors can be represented as:
                                      The eigenvalues η of Matrix (6) have the form
                                                                     ?            ?                  ?           ?
                                                               ps        −C12                 ps        C22 − η
                                                          |TEi =                    , |TMi =                       .                     (34)
                                                                        C11 − ηsin 2 Λ     δ             −2 C21 γ 2
                                                    η = cos Λ + ( γ − δ / 4 )
                                                           2       2      2
                                                                                        ± i sin Λ cos Λ + 2 sin Λ .     2
                                                                                                                                        (33)
                                                                                   Λ2      Λ                     Λ
                                 The elements of the column vector (34) are real values. Based on this, the fields are linearly
                                 polarized. The polarization distribution map data are shown in Figure 5.
                                      Thus, the eigenvectors can be represented as:
                                       Their structure near the optical axes looks like TE and TM modes in a simple anisotropic
                                  crystal, but far from the center there are significant differences. We call them pseudo-TE
                                  and pseudo-TM mods [24].          ps     −C12  distributions
                                                                                               ps            η  fields have interesting
                                                                                                      C22 −these
                                                                TEThe= intensity
                                                                                   ,    TM =  of            .                       (34)
                                                                           C11 − ηdistribution
                                  features. Figure 6 illustrates the intensity                         −C21 
                                                                                                  for differently   polarized pseudo-TM
                                  mode components. While the component Ex does not have any singularities, except for
                                 The  elements
                                  a simple  zeroofon
                                                   the column
                                                     the        vector
                                                         axis, the       (34) are real
                                                                   component             values.
                                                                                    Ey forms      Based
                                                                                              a new        on this,
                                                                                                        type         the fields
                                                                                                               of phase         are linearly
                                                                                                                           singularity——a
                                 polarized.  The polarization
                                  double helical                distribution
                                                  edge dislocation.    Indeed,map      data are
                                                                                  the phase       shown incondition
                                                                                             singularity       Figure 5. is Ey = 0, that is,

Page 8

Photonics 2023, 10, x FOR PEER REVIEW                                                                                                    10 of 18
Photonics 2023, 10, 1044                                                                                                                            8 of 15
                                                                                                                                                              ps
                                                       Figure 5. Self-polarization of the beam in a gyrotropic crystal: (a) pseudo-TE mode TE                      and (
                                                                                 ps
                                                       pseudo-TM mode TM               .


                                                            Their structure near the optical axes looks like TE and TM modes in a simple aniso
                                                       tropic crystal, but far from the center there are significant differences. We call them
                                                       pseudo-TE and pseudo-TM mods [24]. The intensity distributions of these fields have in
                                                       teresting features. Figure 6 illustrates the intensity distribution for differently polarize
                                                       pseudo-TM mode components. While the component Еx does not have any singularitie
                                                       except for a simple zero on the axis, the component Е y forms a new type of phase singu
                                                       larity——a double helical edge dislocation. Indeed, the phase singularity condition
                                                        E y  0 , that is,

                                  Figure 5. Self-polarization of the beam in a gyrotropic 2crystal: (a) pseudo-TE mode            |TEi ps and
                                                                                                              
                                                                                                                            ps
                                 Figure 5. Self-polarization of the beam in a gyrotropic       r
                                                                                         crystal: (a) pseudo-TE  mode   TE     and  (b)
                                  (b) pseudo-TM mode |TMi ps .                    tan 2                                 
                                                                                                      tan  r 2 ; sin  r 2  0 .                                  (3
                                                                                                              
                                                           ps
                                 pseudo-TM mode TM .                                          r   2

                                                                                  2
                                                                                    ?
                                                                             γ r             ? ?
                                                                                                2
                                                                                                            ? ?
                                                                                                                2
                                       Their structure          tan 2φ  =  −          tan Λ   r   ;   sin Λ        = 0.in a simple aniso- (35)
                                                                                                              rmodes
                                                      Thenear     the opticalΛ
                                                            first expression axes
                                                                               (r2 )looksthe
                                                                             describes     like  TE and
                                                                                              double     TMwhile
                                                                                                       helix,       the second describes the distributio
                                 tropic crystal, but  at the periphery. This complex spiral vortex beam is shownWe
                                                          far  from   the center  there   are  significant  differences.         call them
                                                                                                                             in Figure 6.
                                         The first
                                 pseudo-TE      and expression
                                                     pseudo-TM describes
                                                                     mods [24].the
                                                                                Thedouble     helix,
                                                                                       intensity      while the of
                                                                                                  distributions   second
                                                                                                                    these describes
                                                                                                                           fields havethe
                                                                                                                                       in- distri-
                                   bution    at the  periphery.    This  complex    spiral  vortex  beam   is  shown    in Figure
                                 teresting features. Figure 6 illustrates the intensity distribution for differently polarized      6.
                                 pseudo-TM mode components. While the component Еx does not have any singularities,
                                 except for a simple zero on the axis, the component Е y forms a new type of phase singu-
                                 larity——a double helical edge dislocation. Indeed, the phase singularity condition is
                                  E y = 0 , that is,


                                                                             γ (r2 )
                                                                tan 2φ = −                 tan Λ ( r 2 ) ;   sin Λ ( r 2 ) = 0 .            (35)
                                                                             Λ (r2 )

                                 The first expression describes the double helix, while the second describes the distribution
                                 at the periphery. This complex spiral vortex beam is shown in Figure 6.
                                                 (a)                                           (b)                                 (c)

                                   Figure 6. Beams with self-polarization of the pseudo-TM mode in a double gyrotropic crystal: Ex
                  Photonics 2023, 10,(a)
                                      x FOR
                                         andPEER    components; (c) spiral vortex phase (∆n L = 2 · 10−3 , ∆nC = 3 · 10−5 , d = 1 cm).
                                                  REVIEW
                                             Ey (b)                                                                                                                   11
                                                       Figure 6. Beams with self-polarization of the pseudo-TM mode in a double gyrotropic crystal: Е
                                                                                                                        -3
                                                   (a) and Е y describes
                                        The first expression              the double
                                                                (b) components; (c) spiralhelix,
                                                                                           vortexwhile  ( D nsecond
                                                                                                  phasethe    L = 2 ⋅ 10 describes    ⋅10-distri-
                                                                                                                           , D nC = 3the  5
                                                                                                                                            , d = 1cm ).
                                   bution at the periphery. This complex spiral vortex beam is shown in Figure 7.
                                                         The first expression describes the double helix, while the second describes the distr
                                                   bution at the periphery. This complex spiral vortex beam is shown in Figure 7.




                                 Figure 6. Beams with self-polarization of the pseudo-TM mode in a double gyrotropic crystal: Еx
                                 (a) and Е y (b) components; (c) spiral vortex phase ( D nL = 2 ⋅10-3 , D nC = 3 ⋅ 10-5 , d = 1cm ).


                                      The first expression describes the double helix, while the second describes the distri-
                                 bution at the(a)                          (b) vortex beam is shown in Figure(c)
                                                periphery. This complex spiral                                 7.
                                   Figure 7. Intensity distribution (a) in the E(-) left circularly polarized component and phase distribu-
                                   tion for the left (b) circularly and right (c) circularly polarized components.
                                                      Figure 7. Intensity distribution (a) in the E(-) left circularly polarized component and phase d
                                         In contrast to theforcase
                                                      bution      the left
                                                                      of a(b) circularly
                                                                           single        and right
                                                                                    crystal, lines(c)
                                                                                                    ofcircularly polarized
                                                                                                       equal phase     havecomponents.
                                                                                                                             become double
                                   helixes, and the wave front in the vicinity of the singularity is an indirect helicoid. If we
                                                        In contrast
                                   change the sign of the            to the case of
                                                            input polarization      a single crystal,
                                                                                  circulation,         lines
                                                                                                then the     of equaldistribution
                                                                                                           intensity   phase have inbecome do
                                   the optical vortex will not change, but the direction of the phase helix twist will change.helicoid.
                                                   helixes, and  the wave  front in  the vicinity of the  singularity is an indirect
                                                   change the optical
                                   Although in conventional    sign of the input polarization
                                                                        experiments             circulation,
                                                                                      such a helical          then the
                                                                                                      distribution  of intensity distribution i
                                                                                                                       lines of equal
                                                   optical vortex will not change, but the direction of the phase helix twist will change
                                                   hough in conventional optical experiments such a helical distribution of lines of e
                                                   phase is not detected, it has an unexpected manifestation when a linearly polarized b
                                                   propagates through a double gyroanisotropic crystal, which can be represented as a
                                                   circularly polarized beams with the opposite direction of rotation of the vector E, so

Page 9

Photonics 2023, 10, 1044                                                                                                                           9 of 15




                               phase is not detected, it has an unexpected manifestation when a linearly polarized beam
                               propagates through a double gyroanisotropic crystal, which can be represented as a set of
                               circularly polarized beams with the opposite direction of rotation of the vector E, so that at
                               the output, the field pattern can be represented in the form of two circularly polarized beams
                               carrying optical vortices with opposite topological charges. Indeed, such a superposition
                               detects the phase of the vortices so that, as a result, we obtain a quarter-fold intensity
                               spiral. However, these features are characteristic only of their own rays. They can be
                               partially “embedded” into the original light beam from a double crystal in the form of a
                               superposition of eigenbeams.

                               5. Generate Polychromatic Helical Beams
                                    The question is how to extract a beam with a pure helical edge dislocation from the
                               combined beam after the crystal. The easiest way to achieve what you want is to launch a
                               linearly polarized beam into a crystal, that is
                                                                             ?          ?          ? ?
                                                                                 C11              ? 1
                                                                                   ∗        = DĜ      .                                             (36)
                                                                                 −C12               0

                                         Comparing Expressions (34) and (35), the y-component in Expression (36) describes
                                    the same helical edge dislocation as in Expression (34). Generally speaking, the images
                                    presented in Figure 8 have been known for quite a long time in crystallography as Airy
                                    spirals, and are used to distinguish right-handed and left-handed crystals. However, our
                                    path shows a way to create spiral singular beams. Thus, from Expression (35), it follows
                                    that the
Photonics 2023, 10, x FOR PEER REVIEW      qradius    of the first ring dislocation can be found from the following
                                                                                                                  12 condition:
                                                                                                                     of 18
                                    Λ0 = δ r0 + γ r0 = π. Provided that the beam waist at the entrance12face
                                                  2         2
                                                    ?         ?
Photonics 2023, 10, x FOR PEER REVIEW          2         2                                                            of 18of the

                                    crystal is equal to r0 = ρ, the contribution of the energy flux to the ring dislocation is
                                    negligibly small. The configuration of the spiral beam field is shown in Figure 8.




                              Figure 8. Intensity distribution in a spiral vortex beam in (a)— Еx , (b) — Е y components (
                                              Intensity distribution
                               Figure8.8. Intensity                             in a spiral vortex beam in (a)—E , (b)—E components (∆n =
                              Figure 2 ⋅ 10 −3 , Δ nC =distribution
                              Δ nL = −                     3 ⋅−10  −5
                                                                      , d = 1incma ).spiral vortex beam in (a)— Еx x, (b) — Еy y components ( L
                               2 · 10 3 , ∆n       =  3 · 10    5 , d = 1 cm).
                               Δ nL = 2 ⋅ 10 −3 C, Δ nC = 3 ⋅ 10 −5 , d = 1 cm ).
                                   ItItshould
                                        shouldalso
                                                alsobe
                                                     benoted
                                                         notedthatthatthis
                                                                       thisgives
                                                                              givesus usthe
                                                                                          thetechnical
                                                                                                technicalability
                                                                                                          abilityto
                                                                                                                  togenerate
                                                                                                                      generatepolychro-
                                                                                                                                  polychromatic
                              maticIthelical
                                       shouldbeams.
                                               also  To
                                                    be    do
                                                        noted this, you
                                                                 that thisjust  need
                                                                             gives   usto   focus
                                                                                          the       polychromatic
                                                                                               technical
                               helical beams. To do this, you just need to focus polychromatic light into ability tolight           crystal.
                                                                                                                           intoa acrystal.
                                                                                                                      generate    polychro-
                              maticThe   images
                                     helical     shown
                                             beams.   To  in
                                                          do Figure
                                                              this,   9
                                                                    you  are  the
                                                                           just    result
                                                                                 need   to   of a
                                                                                            focus  computer   simulation
                                                                                                    polychromatic
                                     The images shown in Figure 9 are the result of a computer simulation of         light of
                                                                                                                           intothea process.
                                                                                                                                    crystal.
                                                                                                                                      the process.
                              Attention
                                   The    was
                                         imagesdrawn
                                                 shown to  the
                                                          in   fact
                                                              Figure that
                                                                       9 arethe  light
                                                                               the      source
                                                                                    result   of  a was like
                                                                                                   computer a  completely
                                                                                                              simulation
                               Attention was drawn to the fact that the light source was like a completely black             black
                                                                                                                            of the   body—
                                                                                                                                    process.
                                                                                                                                        body—so
                              so that all rays
                              Attention        have only
                                          washave
                                               drawn        a radial
                                                       to the         radius
                                                                fact that   thefor   all source
                                                                                 light   wavelengths.     This
                                                                                                   was like     means thatblack
                                                                                                            a This
                                                                                                               completely      our rays  are
                                                                                                                                     body—
                               that all rays         only   a radial   radius     for all    wavelengths.           means that our       rays are
                              spatially
                              so that allcoherent.
                                          rays have only a radial radius for all wavelengths. This means that our rays are
                               spatially coherent.
                              spatially coherent.




                                Figure9.9.
                              Figure       Polychromatic
                                             Polychromatic     spiral
                                                                  spiralvortex
                                                                            vortexbeam   obtained
                                                                                       beam        at different
                                                                                             obtained          angles
                                                                                                       at different    relative
                                                                                                                    angles      to theto
                                                                                                                             relative   polarizer axes axes
                                                                                                                                         the polarizer
                                Δ nL L==
                              (Figure
                                (∆n          · −10
                                       29.⋅210   , Δ,n∆n
                                                3 −3
                                            Polychromatic=
                                                       C C
                                                           3 ⋅
                                                             = 103−5
                                                                    ·
                                                               spiral ,   −=5 ,1dcm
                                                                        vortex
                                                                       10
                                                                        d         = ).
                                                                                   beam
                                                                                     1    obtained
                                                                                        cm).       at different  angles relative  to the polarizer axes
                               ( Δ nL = 2 ⋅ 10 −3 , Δ nC = 3 ⋅ 10 −5 , d = 1 cm ).
                              6. Optical Vortices
                              6. Optical Vortices
                                  The beams   generated in a double gyroanisotropic crystal have another useful prop-
                              erty—they can carry
                                   The beams      opticalinvortices.
                                             generated      a doubleIndeed, let us passcrystal
                                                                     gyroanisotropic     a circularly polarized
                                                                                               have another     Gaussian
                                                                                                             useful prop-

Page 10

Photonics 2023, 10, 1044                                                                                                                           10 of 15




                                  6. Optical Vortices
                                       The beams generated in a double gyroanisotropic crystal have another useful property—
                                  they can carry optical vortices. Indeed, let us pass a circularly polarized Gaussian beam
                                  through a double crystal. From a mathematical point of view, this means the following:
                                                ?    ? ?                   ?
                                                   1         C11 ± iC12
                                           D Ĝ         =               ∗    =
                                                ±i         ?C12 ± iC ? 11                                      
                                                   cos2 Λ + γ2 + δ4 sinΛ2Λ + i Λδ cos Λ + i Λ
                                                                    2      2                γ
                                                                                              sin Λ exp(±i2φ)
                                                                                                   ?                                                  (37)
                                           =  h             ?          ? 2                                   i .
                                                  i cos2 Λ + γ2 + δ4 sinΛ2Λ − Λδ cos Λ + i Λ
                                                                      2
                                                                                              sin Λ exp(±i2φ)
                                                                                            γ      ?


                                  After passing through a quarter-wave plate, the field will take the form:
Photonics 2023, 10, x FOR PEER REVIEW                                                                                                           13 of 18
                                                                                            cos Λ + i Λ?sin Λ 2exp
                                                                                        δ             γ      ?            !
                                                                                                                ? (± i2φ)
                                                       ?       ?      ?     ?
                                                           1   i      1                 Λ
                                                                 D Ĝ           = 2i                                        .                         (38)
                                                                                             cos2 Λ + γ2 + δ4 sinΛ2Λ
                                                                                                                   2
                                                           i   1      ±i
                                      The polarizer cuts out the Еy —component from the spiral vortex field. Thus, the in-
                                       The polarizer cuts out the Ey —component from the spiral vortex field. Thus, the
                                 tensity andand
                                  intensity  interference distribution
                                                interference           takes
                                                             distribution    thethe
                                                                          takes  form  shown
                                                                                    form     in Figure
                                                                                         shown         10.10.
                                                                                                in Figure




                                  Figure 10. Image of a double charged vortex. (a) Intensity profile, (b) phase.
                                 Figure 10. Image of a double charged vortex. (a) Intensity profile, (b) phase
                                         In fact, we have obtained an ordinary vortex with a double charge, similar to those
                                        In fact, we have obtained an ordinary vortex with a double charge, similar to those
                                   that can be obtained on a simple anisotropic crystal [11,19,25].
                                 that can    be obtained
                                         Consider      in moreon detail
                                                                  a simpletheanisotropic
                                                                                mechanismcrystal         [11,19,25].
                                                                                                of generation       of a double topological charge
                                        Consider      in more   detail   the  mechanism        of  generation
                                   by means of a uniaxial crystal. A typical map of the polarization               of a double     topological
                                                                                                                              distribution     of charge
                                                                                                                                                   a beam
                                 by   means    of  a   uniaxial   crystal.  A   typical    map     of the   polarization
                                   that has passed through an anisotropic medium and a polarization filter (a quarter-wave  distribution      of  a beam
                                 that
                                   platehas
                                          andpassed     through
                                                a polarizer)    is an  anisotropic
                                                                   shown     in Figure     11a. Weand
                                                                                       medium                polarization
                                                                                                       seeathat   right-hand  filter   (a quarter-wave
                                                                                                                                 circular   polarization
                                 plate   and  a   polarizer)   is shown     in  Figure    11a.  We    see  that
                                   is located on the beam axis. This exceptional state of polarization surrounds right-hand    circular    polarization
                                                                                                                                                 a family
                                 isoflocated
                                      ellipses.onAthe     beam axis. This
                                                       characteristic           exceptional
                                                                         property                state ofispolarization
                                                                                      of this family                         surrounds
                                                                                                              the typical ordering        ofaorientation
                                                                                                                                               family of
                                 ellipses.
                                   directionsA characteristic      propertyof
                                                  of the major semiaxis          ofthe
                                                                                    thisellipse.
                                                                                          familyIfiswe  thedraw
                                                                                                             typical   ordering
                                                                                                                    integral         of orientation
                                                                                                                              curves—lines              di-
                                                                                                                                                  tangent
                                 rections    of  the   major  semiaxis     of  the  ellipse.   If  we  draw    integral    curves—lines
                                   at each point to the semi-major axis—we will get a characteristic pattern of spirals (see                  tangent    at
                                 each   point
                                   Figure       to the
                                            11b).   Thesesemi-major     axis—we
                                                            integral curves      are will  get a characteristic
                                                                                     analogous       to lines of forcepattern
                                                                                                                          for aof   spiralspolarized
                                                                                                                                 linearly    (see Figure (at
                                   eachThese
                                 11b).    point)integral
                                                   electriccurves     are analogous
                                                             or magnetic       field. In to   lines
                                                                                           this       of they
                                                                                                  case,          for a linearly
                                                                                                          forcerepresent            polarized
                                                                                                                             the lines               each
                                                                                                                                                 (at of
                                                                                                                                          of force      the
                                 point)   electric or magnetic
                                   inhomogeneously         polarized  field.
                                                                         beam.In this
                                                                                  Suchcase,    they represent
                                                                                            pattern    of integralthecurves     of force
                                                                                                                         linesnear          of the inho-
                                                                                                                                      the singular   point
                                 mogeneously         polarized    beam.    Such    a pattern    of  integral    curves
                                   is similar to the distribution of lines of equal curvature of the wave front near the near   the   singular   point
                                                                                                                                                     waveis
                                 similar   to the   distribution    of  lines  of  equal   curvature      of the  wave   front   near
                                   caustics [26]. They are called umbilic points. In the future, we will keep this analogy, calling     the  wave   caus-
                                 tics  [26].
                                   these     They are
                                          patterns         called umbilic
                                                       surrounding             points. In
                                                                        polarization         the future,polarization
                                                                                          singularities       we will keep     this analogy,
                                                                                                                             umbilics              calling
                                                                                                                                          [11,19,25].
                                 these According
                                         patterns surrounding          polarization
                                                         to the terminology        of J. singularities
                                                                                         Nye [26], an polarization          umbilics
                                                                                                            umbilic is formed            [11,19,25].
                                                                                                                                     in the  vicinity of a
                                   singular point called a C-point. In fact, in the general case, we should not be talking about
                                   points, but about lines of space. As in the scalar case, in the vector field, these lines are
                                   formed by the intersection of two surfaces. The intersection of the line by the observation
                                   plane forms a C-point. On the C-line, the field intensity, in the general case, does not vanish.
                                   The authors of [15–19] distinguish, in the form of characteristic features of the vector field,
                                   the so-called L-surfaces. On this surface, only linear polarization of partial waves exists.
                                   L-surfaces always cover C-lines and separate C-lines corresponding to opposite directions

Page 11

ellipses. A characteristic property of this family is the typical ordering of orientation di-
                                     rections of the major semiaxis of the ellipse. If we draw integral curves—lines tangent at
                                     each point to the semi-major axis—we will get a characteristic pattern of spirals (see Figure
                                     11b). These integral curves are analogous to lines of force for a linearly polarized (at each
Photonics 2023, 10, 1044             point) electric or magnetic field. In this case, they represent the lines of force   of15the inho-
                                                                                                                      11 of
                                     mogeneously polarized beam. Such a pattern of integral curves near the singular point is
                                     similar to the distribution of lines of equal curvature of the wave front near the wave caus-
                                     tics [26]. They are called umbilic points. In the future, we will keep this analogy, calling
                           of polarization, circulation of circular polarization. If at the transition of C-lines the phase
                                     these patterns surrounding polarization singularities polarization umbilics [11,19,25].
                           of the field changes abruptly by π, then at the transition of the L-surface, the direction of
                           circulation of the partial fields abruptly changes.




                                               (a)                                          (b)
                           Figure 11. Distribution map of the polarization state (a) and directions of orientation of the major
                           semiaxis of the ellipse (b) in the cross section of the fundamental Gaussian beam after passing through
                           a uniaxialFigure
                                      crystal.11. Distribution map of the polarization state (a) and directions of orientation of the major
                                     semiaxis of the ellipse (b) in the cross section of the fundamental Gaussian beam after passing
                                     through
                                In our   case,aasuniaxial
                                                   showncrystal.
                                                            in Figure 11a, the pattern of singularities is somewhat different.
                           In the center of the picture is C—a point that is covered by L-line—as a result of a section
                           of the observation plane’s C-line and L-surface; however, instead of the L-line, with the
                           opposite direction of ellipticity, we see a characteristic C-line as a result of section C-plane
                           surface. On the C-surface, light is circularly polarized. Thus, the overall picture of the
                           vector field after a uniaxial crystal is presented as a set of C and L-surfaces nested into
                           each other, which cover the central C-line. Such a difference in the classification introduced
                           in [15–19] with the vector field we are studying after a uniaxial crystal is due to the fact
                           that in these works, the structure of random stochastic fields, which arises as a result of
                           laser beam scattering on random anisotropic inhomogeneities, is studied.
                                 At the same time, we are interested in the process of beam passage through a spatially
                           homogeneous anisotropic medium, in which field states with an unstable singularity
                           structure are possible. As soon as a weak polarization perturbation is introduced into the
                           beam, the picture changes dramatically. A quarter wave plate installed after the crystal can
                           act as such a polarization perturbation.
                                 It is necessary to point out some characteristic features of the picture obtained as a
                           result of the action of the perturbation (see Figure 12). First of all, unstable singularities
                           disappear. The unstable C-point in the center of the picture splits into two single C-points
                           displaced along the beam ϕ = π/2, 3π/2. In the structure of the Figure 12, there are two
                           more simple C-points located on the beam ϕ = 0, π. These two singularities arose as a
                           result of the splitting of the unstable C-line into four symmetrically located C-points: two
                           shifted along the rays ϕ = 0, π to the beam axis.
                                 Two other singularities have shifted along the rays ϕ = π/2, 3π/2 to the periphery. Now,
                           the singularity distribution pattern is structurally stable to the effects of external perturbations.
                                 To convert vector singularities into optical vortices, it is necessary to install a λ/4 plate
                           and a polarizer in a series after the crystal. The λ/4 plate converts the circular polarization
                           to linear polarization, while the polarizer, whose axis is properly oriented, suppresses
                           linear polarization. As a result, zero electric field strength is formed on the beam axis. The
                           occurrence of a phase singularity is easy to understand if we turn to the distribution map of
                           the polarization state (see Figure 11). We will go around C—a point on the beam axis along
                           a closed contour—and follow the rotation of the major semi-axis of the partial wave ellipse.

Page 12

beam, the picture changes dramatically. A quarter wave plate installed after the crystal
                                can act as such a polarization perturbation.
                                     It is necessary to point out some characteristic features of the picture obtained as a
                                result of the action of the perturbation (see Figure 12). First of all, unstable singularities
                                disappear. The unstable C-point in the center of the picture splits into two single C-points
                                displaced along the beam ϕ = π , 3π . In the structure of the Figure 12, there are two
Photonics 2023, 10, 1044                                                                                                   12 of 15
                                                                    2      2
                                more simple C-points located on the beam ϕ = 0, π . These two singularities arose as a
                                result of the tour
                                A complete    splitting  of contour
                                                    of the  the unstable C-line into
                                                                    corresponds      fourrotation
                                                                                  to the  symmetrically   located
                                                                                                  of the axis of theC-points: two
                                                                                                                     polarization
                                shifted  along
                                ellipse by 2π. the  rays  ϕ  = 0, π to the beam  axis.



Photonics 2023, 10, x FOR PEER REVIEW                                                                                                                   15 of 18




                                  polarization to linear polarization, while the polarizer, whose axis is properly oriented,
                                  suppresses linear polarization. As a result, zero electric field strength is formed on the
                                  beam axis. The occurrence of a phase singularity is easy to understand if we turn to the
                                  distribution map of the polarization state (see Figure 11). We will go around C—a point
                                  on the beam axis along a closed contour—and follow the rotation of the major semi-axis
                                  of the partial wave ellipse. A complete tour of the contour corresponds to the rotation of
                                  the axis   ofDistribution
                                                 the polarization
                                          12. Distribution
                                 Figure 12.
                                Figure                        map
                                                               mapof
                                                                          ellipse
                                                                       ofthe
                                                                                    by 2π . ofthe
                                                                                polarizationof
                                                                           thepolarization             beamfield
                                                                                                   thebeam     fieldthat
                                                                                                                      thatpassed
                                                                                                                            passedthrough
                                                                                                                                      throughan  ananisotropic
                                                                                                                                                    anisotropic
                                crystal
                                        Therefore,      a  change      in   the  angle    ϕ from
                                          and a quarter-wave plate. The axes of the quarter-wave
                                 crystal and
                                                                                                       0 to 2πplate
                                                                                                quarter-wave plate
                                                                                                                       corresponds
                                                                                                                          areoriented
                                                                                                                          are  orientedat
                                                                                                                                          to aanchange
                                                                                                                                           atan   angleof
                                                                                                                                                 angle
                                                                                                                                                          in ◦the
                                                                                                                                                        of4545to0


                                tophase
                                 thethe    of  the
                                        coordinate
                                      coordinate    wave
                                                       axes.
                                                    axes.     δ ,  also     from    0  to   2π  .   This  means      that   in  the   vicinity    of the  beam
                                  axis, when passing along a closed contour, a phase difference runs up, which is typical for
                                  fieldsTherefore,
                                       Twowith        asingularities
                                                  phase
                                              other      change      in the
                                                            singularities.     angle
                                                                             have     ϕ from
                                                                                     this
                                                                                 Inshifted case,0 to
                                                                                              along     thecorresponds
                                                                                                       2π
                                                                                                    such   arays
                                                                                                               singularity       3aπchange
                                                                                                                     ϕ = π to,belongs     totothe the
                                                                                                                                               inthe  phase of
                                                                                                                                                     left-hand
                                                                                                                                                   periphery.
                                 the  wavepolarization
                                  circular    δ, also from 0component
                                                                 to 2π. This of     means   that inAthe
                                                                                      the field.           vicinity
                                                                                                        typical        of the
                                                                                                                   picture   2ofbeam  2 axis, when
                                                                                                                                   a double            passing
                                                                                                                                                 helicoid   near
                                Now,
                                 along   the
                                  the axis     singularity
                                          a closed
                                             shows    contour,  distribution
                                                       the presence a phase         patterntopological
                                                                             of adifference
                                                                                   double     is
                                                                                               runsstructurally
                                                                                                       up, which
                                                                                                              chargestable
                                                                                                                       isof   to vortex.
                                                                                                                          typical
                                                                                                                             the   the
                                                                                                                                     foreffectsTheof
                                                                                                                                          fields      external
                                                                                                                                                   with
                                                                                                                                                   wave  phase
                                                                                                                                                           front
                                perturbations.
                                 singularities.
                                  at the periphery  In this   case,
                                                         is cut         such aand
                                                                 by rings,        singularity
                                                                                      each ringbelongs        to the to
                                                                                                    corresponds         left-hand
                                                                                                                           an unstable      ringpolarization
                                                                                                                                      circular     dislocation.
                                 component
                                        At convert
                                       To         of  the
                                            the samevector  field.
                                                          time, the   A   typical    picture
                                                                         vortices obtained
                                                                   singularities                of
                                                                                      into optical   a double
                                                                                                  in anisotropic  helicoid
                                                                                                         vortices, itcrystals   near
                                                                                                                         is necessary   the  axis
                                                                                                                                   are surrounded       abyλthe
                                                                                                                                                    shows
                                                                                                                                            to install       nu-
                                presence      of  a double     topological         charge   of the    vortex.    The    wave    front    at the   periphery    4is
                                  merous ring dislocations, while in our case, these dislocations are almost never observed.
                                plate    and    a polarizer
                                                          each in                                                   λ
                                 cut
                                  Theby   rings,
                                        degree     and
                                                  of  splitting  ring     series after the
                                                                     ofa dislocations
                                                                         corresponds       to ancrystal.
                                                                                           depends       on The
                                                                                                    unstable thering   4dislocation.γ / Λ . Thethe
                                                                                                                           plate converts
                                                                                                                   coefficient                          circular
                                                                                                                                                   greater    the
                                        At  the   same     time,     the   vortices    obtained      in  anisotropic       crystals
                                  gyration of the crystal, the less noticeable the dislocations, but at the same time, the coef-       are   surrounded       by
                                 numerous ring dislocations,              while2 in our case, these dislocations are almost never observed.
                                                            Ex dS         E y dS , sodepends
                                                                  2
                                  ficient
                                The        decreases
                                       degree     of splitting      of /dislocations       that in the   on final   analysis, the
                                                                                                             the coefficient        γ/Λ.spiral
                                                                                                                                             Thevortex
                                                                                                                                                   greaterbeam
                                                                                                                                                             the
                                  can disappear
                                 gyration     of theunder
                                                        crystal, thethe  condition      Δ nC >>the
                                                                             less noticeable        Δ nLdislocations,
                                                                                                           in which the     butcircular
                                                                                                                                   at the birefringence
                                                                                                                                             same time, the      is
                                                                R        2       R      2
                                  much greater
                                 coefficient         than the linear
                                                 decreases         | Ex | dS/ one. Ey dS, so that in the final analysis, the spiral vortex
                                 beam can disappear under the condition ∆nC >> ∆n L in which the circular birefringence
                                  7. much
                                 is  Experimental
                                            greater than Obtaining
                                                               the linear   of Singular
                                                                                one.        Beams in Gyroanisotropic Crystals
                                        At present, our attention is most attracted to polychromatic singular beams. As a re-
                                 7. Experimental Obtaining of Singular Beams in Gyroanisotropic Crystals
                                  sult, we have focused our efforts on the generation of helical edge dislocations embedded
                                       At present, our
                                  in polychromatic        attention is most attracted to polychromatic singular beams. As a
                                                      beams.
                                 result,The
                                         wescheme
                                             have focused
                                                      of the our efforts on the
                                                             experimental       generation
                                                                             setup   is shownofinhelical
                                                                                                   Figuredge
                                                                                                          13. dislocations embedded
                                                                                                              The key element    of the
                                 in polychromatic     beams.
                                  installation is a white light source, which is a halogen lamp equipped with a spherical
                                  mirror.   scheme
                                       TheThe        of the
                                                 angular     experimental
                                                           divergence        setup
                                                                        of the beam is shown    in Figure
                                                                                        after passing     13. The
                                                                                                       through    key
                                                                                                                the    element
                                                                                                                     spatial         the
                                                                                                                             lensoffilter
                                 installation  is a white light
                                                          0     source, which  is a halogen   lamp  equipped   with a spherical
                                  becomes less than 4 . The beam then passes through a polarizer to become linearly po-         mirror.
                                 The   angular divergence of the beam after passing through the spatial lens filter becomes
                                  larized.   ◦
                                 less than 4 . The beam then passes through a polarizer to become linearly polarized.




                                 Figure       Schemeof
                                          13. Scheme
                                 Figure 13.          ofthe
                                                        theexperimental
                                                            experimentalsetup:
                                                                           setup:1—halogen
                                                                                   1—halogenlamp;
                                                                                               lamp;2—spatial
                                                                                                     2—spatiallens filter;
                                                                                                                lens        3,9—polarizers;
                                                                                                                       filter; 3,9—polariz-
                                 4,6,8—lenses;   5—LiNbO
                                 ers; 4,6,8—lenses; 5—LiNbO
                                                          3 crystal; 7—SiO
                                                               3 crystal; 7—SiO
                                                                            2 crystal; 10—CCD    camera, Ĉ—unit vector
                                                                                 2 crystal; 10—CCD camera, Ĉ —unit vector of  optical axes.
                                                                                                                                   of optical
                                 axes.

                                      After that, the beam is focused by a lens with a focal length of 3 cm into a LiNbO3
                                 crystal. Next, we focus the beam again, but now into the SiO2 crystal. The optical axes of
                                 the crystals are directed along the beam axes. The beam image is projected onto the screen

Page 13

Photonics 2023, 10, 1044                                                                                                                          13 of 15




                                        After that, the beam is focused by a lens with a focal length of 3 cm into a LiNbO3
                                  crystal. Next, we focus the beam again, but now into the SiO2 crystal. The optical axes of
Photonics 2023, 10, x FOR PEER REVIEW
                                  the crystals are directed along the beam axes. The beam image is projected onto the 16              of 18
                                                                                                                                   screen
                                  of a CCD camera and processed by a computer.
                                        We considered the intensity distribution of the singular beam as a function of the
                                  direction  of the
                                         Figure     polarizer
                                                14 shows       axesimages
                                                          typical   α.      of a singular beam. When the angle is α = 90◦0 , a pure
                                        Figure
                                   spiral       14beam
                                           vortex  showsdislocation
                                                          typical images    of a singular
                                                                     is embedded          beam.
                                                                                      in the     When
                                                                                             beam.  It isthe
                                                                                                           important   α=
                                                                                                              angle is to    90 that
                                                                                                                          note   , a pure
                                                                                                                                       the
                                  spiral  vortex are
                                   dislocations   beam
                                                     notdislocation
                                                          washed out is in
                                                                         embedded    in the light,
                                                                           polychromatic     beam.but      important
                                                                                                    It isare          to note
                                                                                                             seen as clear             the
                                                                                                                                thatlines
                                                                                                                            spiral
                                  dislocations   are not washed
                                   with four branches.             out inofpolychromatic
                                                          The method         generation oflight,   but are seen
                                                                                             polychromatic        as clearspiral
                                                                                                               singular     spiralvortex
                                                                                                                                     lines
                                  with   four branches.   The  method     of generation   of polychromatic     singular   spiral
                                   beams described in this paper can be applied by other researchers to analyze the proper-        vortex
                                  beams
                                   ties of described in this angular
                                           spin and orbital  paper can   be applied[5,9,22]
                                                                     momentum        by other researchers to analyze the properties
                                  of spin and orbital angular momentum [5,9,22].




                                  Figure 14. Scheme
                                  Figure 14. Scheme of of the
                                                          the distribution
                                                               distribution of
                                                                            of the
                                                                               the light
                                                                                     light flux over the
                                                                                           flux over     angular spectrum
                                                                                                     the angular spectrum in
                                                                                                                          in the
                                                                                                                             the Bessel–Gauss
                                                                                                                                 Bessel–Gauss
                                  beam (∆n L = 1.8 · 10−3−3 , ∆nC = 2.8 · 10
                                                                           −5
                                                                              −5 , d = 0.5 cm).
                                  beam ( Δ nL = 1.8 ⋅ 10 , Δ nC = 2.8 ⋅ 10 , d = 0.5 cm ).
                                  8. Conclusions
                                  8. Conclusions
                                       A type of monochromatic and polychromatic singular beams carrying helical edge
                                         A type and
                                  dislocations     of monochromatic
                                                         optical vorticesand  has polychromatic
                                                                                   been theoretically  singular   beams carrying
                                                                                                          and experimentally              helical Such
                                                                                                                                       studied.     edge
                                   dislocations
                                  beams     can beand    optical
                                                     created      vortices
                                                              using   natural has  been theoretically and experimentally
                                                                                objects—gyroanisotropic          crystals. A linearly   studied.   Such
                                                                                                                                              polarized
                                   beams can be created
                                  monochromatic                using natural objects—gyroanisotropic
                                                         or polychromatic        beam of light passing through    crystals.twoA linearly      polarized
                                                                                                                                    gyroanisotropic
                                   monochromatic
                                  crystals               or polychromatic
                                              with opposite     signs of the beam        of light
                                                                                  gyration           passing through
                                                                                              and polarization              two gyroanisotropic
                                                                                                                     coefficients      creates spiral
                                   crystalsedge
                                  vortex      withdislocations—also
                                                    opposite signs of called
                                                                          the gyration     and polarization
                                                                                   Airy rings.    The expressionscoefficients
                                                                                                                       that form  creates    spiral
                                                                                                                                      the basis   ofvor-
                                                                                                                                                      the
                                  described     phenomenon are written
                                   tex edge dislocations—also                    down.
                                                                       called Airy        These
                                                                                       rings.   Theexpressions
                                                                                                      expressions enable
                                                                                                                      that us
                                                                                                                            formto analyze
                                                                                                                                     the basis  various
                                                                                                                                                  of the
                                  cases  of thephenomenon
                                   described      propagation are of singular     beams.These
                                                                      written down.         As experimental
                                                                                                   expressions objects,
                                                                                                                   enable us wetoused      a system
                                                                                                                                     analyze     variousof
                                   casescrystals:
                                  two               LiNbO3 andofSiO
                                          of the propagation             2 , whose
                                                                      singular       optical
                                                                                   beams.   Asaxes    are directed
                                                                                                 experimental         alongwe
                                                                                                                   objects,         beama axes.
                                                                                                                              theused         system The of
                                  beam    of light produced
                                   two crystals:    LiNbO3 and  by SiO
                                                                    a halogen
                                                                         2, whose lamp   is transformed
                                                                                     optical                 by this system
                                                                                               axes are irected       along the      beama axes.
                                                                                                                                 in such       way that
                                                                                                                                                     The
                                  abeam
                                     polychromatic       phase singularity
                                           of light produced      by a halogen  withlamp
                                                                                      a clearly   defined central
                                                                                             is transformed     by thisspiral  line isinbuilt
                                                                                                                           system          suchinto
                                                                                                                                                  a wayit.
                                        The    method     described    in  this article  can   be  applied    by  other  researchers
                                   that a polychromatic phase singularity with a clearly efined central spiral line is built                to  analyze
                                  the
                                   intoproperties
                                        it.           of spin and orbital moments in free space [27,28], to analyze the shapes and
                                  properties    of  beams   that carryinathis
                                         The method described               topological    charge,
                                                                                 article can         to studybyanisotropic
                                                                                               be applied                       media [29,30],
                                                                                                                   other researchers                 and
                                                                                                                                             to analyze
                                   thestudy
                                  to           the properties
                                       properties     of spin andof orbital
                                                                     topological     charges
                                                                               moments           [31–36]
                                                                                           in free  spaceboth     in anisotropic
                                                                                                            [27,28],  to analyze the   media
                                                                                                                                           shapesandand in
                                  weakly
                                   propertiesturbulent
                                                 of beams atmospheric
                                                              that carrymedia.
                                                                             a topological charge, to study anisotropic media [29,30],
                                        Thestudy
                                   and to     resultstheobtained   in this
                                                          properties         publicationcharges
                                                                       of topological      can be used     in modern
                                                                                                      [31–36]  both in photonics,
                                                                                                                         anisotropicfor        example,
                                                                                                                                            media    and
                                  to  develop    improved     configurations
                                   in weakly turbulent atmospheric media.         of the  shape    and  types  of  optical   beams,      to find  states
                                  (C-lines
                                         Theand   L-surfaces)
                                               results   obtainedof polarization     of anisotropic
                                                                    in this publication                mediainthat
                                                                                              can be used            cannot
                                                                                                                 modern        be createdfor
                                                                                                                             photonics,        byexam-
                                                                                                                                                   other
                                  means,     and   to  overcome     any   technical    limitations     associated    with
                                   ple, to develop improved configurations of the shape and types of optical beams, to find the    improvement          of
                                  design    instruments     and  apparatus,      including    those   for medical    research.
                                   states (C-lines and L-surfaces) of polarization of anisotropic media that cannot be created
                                  by other means, and to overcome any technical limitations associated with the improve-
                                  ment of design instruments and apparatus, including those for medical research.

                                  Author Contributions: Conceptualization, Y.E. and A.R.; methodology, Y.E.; validation, Y.E. and
                                  A.R.; formal analysis, Y.E. and A.R.; investigation, Y.E. and A.R.; resources, Y.E. and A.R.; writing—
                                  original draft preparation, Y.E.; writing—review and editing, Y.E. and A.R.; supervision, Y.E.; pro-
                                  ject administration, Y.E. and A.R. All authors have read and agreed to the published version of the

Page 14

Photonics 2023, 10, 1044                                                                                                               14 of 15




                                   Author Contributions: Conceptualization, Y.E. and A.R.; methodology, Y.E.; validation, Y.E. and A.R.;
                                   formal analysis, Y.E. and A.R.; investigation, Y.E. and A.R.; resources, Y.E. and A.R.; writing—original
                                   draft preparation, Y.E.; writing—review and editing, Y.E. and A.R.; supervision, Y.E.; project adminis-
                                   tration, Y.E. and A.R. All authors have read and agreed to the published version of the manuscript.
                                   Funding: This research received no external funding.
                                   Institutional Review Board: Not applicable.
                                   Informed Consent Statement: Informed consent was obtained from all subjects involved in the study.
                                   Data Availability Statement: The data presented in this study are available upon request from the
                                   respective author.
                                   Conflicts of Interest: The authors declare no conflict of interest.

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Source notes & attribution
  1. https://rexresearch.com/CISSMetamaterial/photonics-10-01044.pdf

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All 1 figures

Source illustrations for Chirality & spin. Captions identify the document and evidence type.

Keep following.

Thematic connections, not evidence of a shared mechanism